Quantitative Aptitude Quiz | 20-May-2020 | |Bank, SSC, PSC, Railway|

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Quantitative Aptitude Quiz | 20-May-2020 |
|Bank, SSC, PSC, Railway|

(With Answer key and Solutions)

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1. Sol. (D)

Let B reached the distance in x minutes/ माना B दूरी को x मिनट में तय करता है ।

Time taken by A/A द्वारा लिया गया समय = (x + 20) min/मिनट

According to question/प्रश्नानुसार,

¾ = x/ (x + 20)

3x + 60 = 4x

x = 60 min/मिनट

Time taken by A/ A द्वारा लिया गया समय = 80 min/मिनट = 1 (1/3) hrs/घंटे

 2. Sol. (B)
Relative speed/ सापेक्ष चाल = (25 – 5) = 20 km/किमी.
Length of train/ ट्रेन की लंबाई = (50/2) × (27/2) = 75 m. /मी.

 3. Sol. (B)
Let the marked price be Rs. x/ माना अंकित मूल्य x रु. है ।
S.P. = 0.9 x
0.9 x = 16560
x = 18400
C.P. = (16560 × 100)/ 115 = 14400
% profit/ लाभ = {(18400 – 14400)/ 14400} × 100 = 27 (7/9)%

 4. Sol. (A)
Let the share of P be Rs. x/ माना P का हिस्सा x रु. है ।
then Q's share/ तो Q का हिस्सा = x + 30
and R's share/ और R का हिस्सा = (x + 30) + 60
x + x + 30 + x + 90 = 300
x = 60
Ratio/ अनुपात = 60: (60 + 30): (60 + 90) = 2: 3: 5

 5. Sol. (A)
xy = 1344 × 24 … (i)
(x – y) = 80 … (ii)
(x + y)2 – (x – y)2 = 4xy
(x + y)2 = 4 × 1344 × 24 + 6400
= 135424
x + y = 368

 6. Sol. (C)
(a + b)/ (a – b) = 1/5
5a + 5b = a – b
4a = – 6b
a/b = – 3/2
{(a3 – b3)/ (a3 + b3)} = [{(a/b)3 – 1}/ {(a/b)3 + 1}]
= [{(– 3/2)3 – 1}/ {(– 3/2)3 + 1}]
= [{(– 27/8) – 1}/ {(– 27/8) + 1}]
= 35/19

 7. Sol. (D)
Let the angle be x/ माना कोण x है ।
According to the question/ प्रश्नानुसार,
(180o – x) = 4x – 20o
5x = 200o
x = 40o

 8. Sol. (A)
Let each exterior angle be x/माना प्रत्येक वाह्यकोण x है ।
Then each interior angle/तो प्रत्येक अन्तः कोण = 5x
x + 5x = 180
6x = 180
x = 30
Number of sides/भुजाओं की संख्या = 360/30 = 12

 9. Sol. (B)
a2 – 3a + 1 = 0
On dividing both sides by a, we get/a से दोनों ओर भाग करने पर, हम प्राप्त करते हैं
a – 3 + (1/a) = 0
a + (1/a) = 3
Now/अब, a5 + (1/a5) = {a3 + (1/a3)} {a2 + (1/a2)} – {a + (1/a)}
= [{a + (1/a)3} – 3 {a + (1/a}] [{a + (1/a)2} – 2] – {a + (1/a)}
= {(3)3 – 3 (3)} {(3)2 – 2} – 3
= (27 – 9) × 7 – 3
= 126 – 3 = 123

10. Sol. (B)
Let/माना f(x) = x2 – 7x + 15
Now putting/अब रखने पर, x = 2/3
f (2/3) = (2/3)2 – 7 (2/3) + 15
= 4/9 – 14/9 + 15
= (4 – 42 + 135)/ 9

= 97/9 = 10 (7/9)

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