Quantitative Aptitude Quiz | 10-July-2020 ||Answer key with Solution|
Useful for BANK. SSC, RAILWAY, UPSC, PSC, WBCS
1. Sol. (C)
Speed downstream/अनुप्रवाह चाल = (2/ 15) × 60 = 8 kmph/किमी./घंटा
Speed downstream/अनुप्रवाह चाल = 5 kmph/किमी./घंटा
Speed of current/धारा की चाल = {(8 – 5)/ 2} = 3/2 = 1.5 kmph/किमी./घंटा
2. Sol. (A)
Let A's speed/माना A की चाल = x kmph/किमी./घंटा
B's speed/B की चाल = y kmph/किमी./घंटा
According to the question/प्रश्नानुसार,
{(30/x) – (30/y)} = 2 … (I)
{(30/y) – (30/2x)} = 1 … (I)
On solving (I) and (II), we get/(I) और (II) को हल करने पर,
x = 5 kmph/किमी./घंटा
3. Sol. (C)
Let incomes of P, Q and R be 3x, 7x and 4x. / माना P, Q और R की आय 3x, 7x और 4x है।
Their expenses are 4y, 3y and 5y / उनके खर्चे 4y, 3y और 5y हैं ।
According to question, / प्रश्नानुसार,
3x – 4y = (1/8) × 3x
(21x/8) = 4y
21x = 32y
A's savings/A की बचत = (3/8) × (32/21) y = 4y/7
B's savings/B की बचत = 7x – 3y = 7 × (32/21) y – 3y = 23y/3
C's savings/C की बचत = 4x – 5y = 4 × (32/21) y – 5y = 23y/21
Required ratio/अà¤ीष्ट अनुपात = (4y/7): (23y/3): (23y/21) = 12: 161: 23
4. Sol. (B)
Let/माना CP = 100, then profit/तो लाठ= Rs. 320
S.P./विक्रय मूल्य = Rs. 420
New C.P. /नया क्रय मूल्य = 125% of Rs.100 = Rs. 125
New S.P. /नया विक्रय मूल्य = Rs. 420
Profit/लाठ= Rs. (420 – 125) = Rs. 295
Required percentage/अà¤ीष्ट प्रतिशत = {(295/ 420) × 100} %
= (1475/ 21) % = 70% (approximate/लगà¤à¤—)
5. Sol. (D)
Wheat/गेंहूँ = 9
Rice/चावल = 10
Sugar/चीनी = 8
Required/अà¤ीष्ट % = (9/10) × 100 = 90%
6. Sol. (A)
Rajeev can complete a work in (12 × 8) hrs. = 96 hrs. /घंटे
Raghav can complete the same work in (8 × 10) hrs. = 80 hrs. /घंटे
Both will finish the work in/दोनों मिलकर काम पूरा करेंगें
= 1/ {(1/ 80) + (1/ 96)} hrs. /घंटे
= (480/11) hrs. /घंटे
Number of days required to complete this work/इस काम को पूरा करने में आवश्यक दिनों की संख्या
= (480/11) × (1/8) = 60/11 = 5 (5/ 11) hrs. /घंटे
7. Sol. (B)
Let speed of the boat/माना नाव की चाल = x km/hr. / (किमी. /घंटा)
and speed of the current/और धारा की चाल = y km/hr. / (किमी. /घंटा)
Downstream speed/अनुप्रवाह चाल = (x + y) km/hr. / (किमी. /घंटा)
Upstream speed/ऊर्ध्वप्रवाह चाल = (x + y) km/hr. / (किमी. /घंटा)
According to the question/प्रश्नानुसार,
2 (x + y) = 3 (x – y)
2x + 2y = 3x – 3y
x = 5y
x: y = 5: 1
8. Sol. (D)
According to the question/प्रश्नानुसार,
504 = (3200 × r × 7)/ 300
r = 6.75% = 6 (3/4) %
9. Sol. (B)
Ratio between their efficiency/उनकी कार्यक्षमताओं में अनुपात = 3: 1
Ratio between their time/उनके समयों में अनुपात = 1: 3
According to the question/प्रश्नानुसार,
(3 – 1) = 32
2 = 32
1 = 16
3 = 48
Required time/अà¤ीष्ट समय = {48/ (3 + 1)} = 12 minutes/मिनट
10. Sol. (C)
According to the question/प्रश्नानुसार,
25% + 60 = 60% - 80
140 = 35%
1% = 4
100% = 400
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