Quantitative Aptitude Quiz | 24-June-2020 | |Answer key with Explanation|

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Quantitative Aptitude Quiz | 24-June-2020 |

|Answer key with Explanation|

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Useful for BANK. SSC, RAILWAY, UPSC, PSC, WBCS

 1. Sol. (C)
40 M = 60 W = 80 C
2 M = 3 W = 4 C
Now/अब, 10 M + 10 W + 10 C = 10 M + (20/3) M + 5 M
= (65/3) M
Required number of days/अभीष्ट दिनों की संख्या = {(40 × 6 × 3)/ (65 × 2)}
= 72/13 = 5 (7/13) months/माह

 2. Sol. (B)
x = 6 + (1/x)
x – (1/x) = 6
x2 + (1/x2) – 2 = 36
x2 + (1/x2) = 38
x4 + (1/x4) = 1444 – 2
x4 + (1/x4) = 1442

 3. Sol. (C)
M1 × d1 = M2 × d2
10 M × 15 = (10 M × 5) + (10 M + 10 W) × 5
150 M = 50 M + 50 M + 50 W
50 M = 50W
1 M = 1 W [10 M = 10 W]
Again/पुनः, M1 × d1 = M2 × d2
10 W × 15 = 25 W × d2
d2 = 6 days/दिन

 4. Sol. (B)
2 M + 4 B = (1/10), 4 M + 5 B = (1/6)
⇒ 20 M + 40 B = 24 M + 30 B
⇒ 4 M = 10 B,
⇒ 2 M = 5 B
⇒ M: B = 5: 2

5. Sol. (A)
(A + B)'s one day work/(A + B) का 1 दिन का कार्य = (1/30) + (1/20) = 1/12
(A + C)'s one day work/(A + C) का 1 दिन का कार्य = (1/30) + (1/10) = 2/75
Two days work/दो दिन का कार्य = (1/12) + (2/15) = (5 + 8)/ 60 = 13/60
8 day's work/8 दिन का कार्य = (13/60) × 4 = 13/15
Remaining work/शेष कार्य = 1 – (13/15) = 2/15
9th day (A + B) will do/नवें दिन (A + B) करेगा = (1/12)th part/भाग
Remaining work/शेष कार्य = (2/15) – (1/12) = 1/20
Now, (A + C) will do that work/अब, (A + C) उस कार्य को करेगा = (1/20) × (15/2) = 3/8
Total number of days/कुल दिनों की संख्या = 9 (3/8) days/दिन

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